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Math 375 - 11/2
Math 375
Published
November 3, 2017
Modified
November 16, 2017
Uniqueness Theorem • Theorem ○ Suppose f(A_1,…,A_n ) is a function of A_1,…,A_n∈Rn ○ That satisfies Linearity and Alternating § f(B+C,A_2,…,A_n )=f(B,A_2,…,A_n )+f(C,A_2,…,A_n ) § f(t⋅A_1,A_2,…,A_n )=t⋅f(A_1,A_2,…,A_n ) § f(A_1,A_2,…,A_i,..,A_j,…A_n )=−f(A_1,A_2,…,A_j,..,A_i,…A_n ) ○ Then f(A_1,…,A_n )=det(A_1,…,A_n )⋅f(I_1,…,I_n ) where § I_1=[1,0,0,…,0] § I_2=[0,1,0,…,0] § ⋮ § I_n=[0,0,0,…,1] • Proof ○ f(A_1,…,A_n ) ○ =f(a_11 I_1+a_12 I_2+…+a_1n I_n,…,a_n1 I_1+a_n2 I_2+…+a_nn I_n ) ○ =∑_█(1≤i_1,i_2,…,i_n≤n@all different)^n▒a_(1i_1 ) a_(2i_2 )…a_(ni_n )⋅f(I_(i_1 ),I_(i_2 ),…,I_(i_n ) ) ○ =∑_█(1≤i_1,i_2,…,i_n≤n@all different)^n▒a_(1i_1 ) a_(2i_2 )…a_(ni_n )⋅sign(i_1,…,i_n )⋅f(I_1,I_2,…,I_n ) ○ =f(I_1,I_2,…,I_n )⋅∑_█(1≤i_1,i_2,…,i_n≤n@all different)^n▒a_(1i_1 ) a_(2i_2 )…a_(ni_n )⋅sign(i_1,…,i_n ) ○ =f(I_1,I_2,…,I_n )⋅det(A_1,…,A_n ) • Example ○ |■8(A_(k×k)&0@C_(l×k)&B_(l×l) )|=|■(a_11&…&a_1k&&&@⋮&⋱&⋮&&&
@a_k1
&…&a_kk&&&
@c_11
&…&c_1k&b_11&…&b_1l@⋮&⋱&⋮&⋮&⋱&⋮
@c_l1
&…&c_lk&b_l1&…&b_ll )|=detA⋅detB ○ Consider a function f that satisfies the Uniqueness Theorem § f((A_1 ) ̅+(A_1 ) ̅ ̅,A_2,…,A_n )=f((A_1 ) ̅,A_2,…,A_n )+d((A_1 ) ̅ ̅,A_2,…,A_n ) § f(tA_1,A_2,…,A_n )=f(A_1,A_2,…,A_n ) § f(A_1,A_2,…,A_i,..,A_j,…A_n )=f(A_1,A_2,…,A_j,..,A_i,…A_n ) ○ Let f_BC (A_1,…,A_k )=|■8(A_(k×k)&0@C_(l×k)&B_(l×l) )| with B,C fixed, and A as variable § f_BC (A_1,…,A_k ) § =det(A_1,…,A_k ) f_BC (I_1,…,I_k ) § =detA⋅|■(1&&&&&@&⋱&&&&@&&1&&&
@c_11
&…&c_1k&b_11&…&b_1l@⋮&⋱&⋮&⋮&⋱&⋮
@c_l1
&…&c_lk&b_l1&…&b_ll )| § =detA⋅|■(1&&&&&@&⋱&&&&@&&1&&&@&&&b_11&…&b_1l@&&&⋮&⋱&⋮@&&&b_l1&…&b_ll )| § =detA⋅|■(I&@&B)| ○ Let g(B)=|■(I&@&B)| that satisfies the Uniqueness Theorem § g(B)=detB⋅g(I)=detB⋅|■(1&&@&⋱&@&&1)|=detB ○ Therefore |■8(A_(k×k)&0@0&B_(l×l) )|=detA⋅detB Properties of Determinant • det〖(AB)=detA⋅detB 〗 (where A_(n×n), B_(n×n)) ○ detA⋅detB ○ =|■8(A&0@I&B)| ○ =|■8(0&−AB@I&B)| ○ =(−1)
(n
2 ) |■8(I&B@0&−AB)| ○ =(−1)
(n
2 ) detI⋅det(−AB) ○ =(−1)
(n
2 )⋅det(−AB) ○ =(−1)
(n
2 ) (−1)^n det(AB) ○ =(−1)
(n
2+n) det(AB) ○ =det(AB) • Power of Determinants ○ det(A^n )=det(A⋅A…A)=det〖(A)⋅〗 det(A)…det(A)=(detA )^n • Determinant of Inverse ○ If A has an inverse(A^(−1)), and detA≠0, then ○ A^(−1) A=I ○ ⇒det〖A^(−1) 〗⋅detA=detI=1 ○ ⇒det〖A^(−1)=1/detA 〗 • Matrix Product and Determinant ○ |■8(A_(n×n)&0@I&B_(n×n) )| ○ =|■(a_11&…&a_1n&&&@⋮&⋱&⋮&&&
@a_n1
&…&a_nn&&&
@1
&&&b_11&…&b_1n@&⋱&&⋮&⋱&⋮@&&1&b_n1&…&b_nn )| ○ =|■(0&…&a_1n&−a_11 b_11&…&−a_11 b_1n@⋮&⋱&⋮&⋮&⋱&⋮
@0
&…&a_nn&−a_n1 b_11&…&−a_n1 b_1n@1&…&0&b_11&…&b_1n@⋮&⋱&⋮&⋮&⋱&⋮
@0
&…&1&b_n1&…&b_n )|=… ○ =|■(0&…&0&−∑_(i=1)^n▒〖a_1i b_i1 〗&…&−∑_(i=1)^n▒〖a_1i b_in 〗@⋮&⋱&⋮&⋮&⋱&⋮
@0
&…&0&−∑_(i=1)^n▒〖a_ni b_i1 〗&…&−∑_(i=1)^n▒〖a_ni b_in 〗
@1
&…&0&b_11&…&b_1n@⋮&⋱&⋮&⋮&⋱&⋮
@0
&…&1&b_n1&…&b_nn )| ○ =|■8(0&−AB@I&B)|